How many moles of CaCl2 are in 15.0mL of 0.430M solution? If you add enough AgNO3 to CaCl2 solution, what mass of AgCl would it make?
2AgNO3+CaCl2–> 2AgCl(s) + Ca(NO3)2
If I did my math correct, there are 28.7 moles of CaCl2. (If I am not correct, please let me know!) I am a little confused as to how to proceed with the second part of the equation. I would like to figure the answer out, but am not sure as to what steps to take